inches be the better deal?If a large pizza of 18 inches cost $15, at what price and below would a medium pizza of 10?
Not sure if I did this right because the final result is so low, but here is my logic
Find area of 18" pizza. P = pi (I rounded to 3.14)
r = 18 / 2 = 9
A = P * r^2 = 3.14 * 9^2 = 254.31
Area per dollar = Area of pizza / Price = 254.31 / 15 = 16.956 area of pizza per 1$
Compare to 10" pizza
r = 5
A = 3.14 * 5^2 = 78.5
Area per dollar = Area of pizza / Price
For a better deal, want area per dollar to be %26gt;= 16.956
16.956 %26lt;= Area of pizza / price
16.956 %26lt;= 78.5 / price
price %26lt;= 78.5 / 16.956
price %26lt;= $4.63If a large pizza of 18 inches cost $15, at what price and below would a medium pizza of 10?
get the area per dollar
(pi) * r^2 = 3.14*9^2 = 254.47
per dollar
254.47 / 15 = 16.96 square inches per dollar
(pi) * r^2 = 3.14*5^2 = 78.54
78.54/16.96 = 4.63
so you'd have to pay less than 4.63 to get a better deal with a 10 inch medium pie.
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