Math Question; deals with probability?

You and two friends visit a pizza shop. There are 13 toppings. 8 toppings are meat and the rest are vegetable. Each of you orders a different topping (no repeats) at random. What is the probability that your group orders only meat toppings?



I'm looking for answer and how you got it. Thank you muchoo :]Math Question; deals with probability?
The first person has a 8/13 chance of getting a meat topping. The second person has a 7/12 chance because there are no repeats, which means the third person would have a 6/11 chance. Since there are three of you, you multiply 8/13 * 7/12 * 6/11. That gives you a 19.6% chance or 336/1716
Odds for first person to pick a meat topping: 8/13

Odds for second person to pick meat: 7/12

Odds for third person to pick meat: 6/11



Total odds = 8/13 * 7/12 * 6/11 = 336 / 1716 = 28 / 143 = 19.58%



First answerer is dead wrong. Second and third are correct.Math Question; deals with probability?
The first person chooses a meat topping = 8/13.



The second person = 7/12.



The third person = 6/11.



p(all 3 choose meat) = (8/13)*(7/12)*(6/11).
1/120. Multiply 3 and 13 and 8 together.